inequality - if $\sqrt{\log_4(\log_3(\log_2(x^2-2x+a)))}$ is defined for all x={set of real numbers} then find the valid interval for "a". - Mathematics Stack Exchange
log2(x-1) = 4 Solving logarithm problem by Hand - YouTube
log2(x^2-4)-3 log 2(x+2/x-2) > 2
The roots of the equation log2(x^2 - 4x + 5) = (x - 2) are
How to solve for x in this equation log base 3 (x^2 + x - 6) = log base 3 (x^2 + 7x + 12) - 2/3log base 9 (8) - Quora
The roots of the equation `log2(x^2-4x+5)=(x-2)` are - YouTube